I am trying to figure out how to set this problem up. I know its similar to # 7 but i am confused because I don't know how to do it since the to two cables have different angles.
What I did was I figured since the object is suspended, the force upward must be the same as the force of gravity, so I drew a force upward of 37N. Then, I found the force in the wire at 46˙ as the hypotenuse of the resultant triangle. The force in the horizontal wire, similarly, had to be the same as the horizontal force in the opposite direction, which I again found using trig. Does that help at all?
5 comments:
What I did was I figured since the object is suspended, the force upward must be the same as the force of gravity, so I drew a force upward of 37N. Then, I found the force in the wire at 46˙ as the hypotenuse of the resultant triangle. The force in the horizontal wire, similarly, had to be the same as the horizontal force in the opposite direction, which I again found using trig. Does that help at all?
Did you use the law of sines to figure that out?
No, just SOH CAH TOA.
Oh! Thanks.
Oh awesome thanks a lot that helped.
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