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AP-B Physics

Sunday, September 18, 2011

UTexas HW2 #16

How do i calculate for the horizontal component?
Posted by Rob Mellone at 7:24 AM

2 comments:

Naveen V said...

just saying i already helped him, and he got it so need to respond to this

September 18, 2011 at 9:46 AM
Rob Mellone said...

thank you Naveen

September 18, 2011 at 4:44 PM

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