Thursday, September 29, 2011

# 8

For this problem, it states A 5 kg bucket of water is raised from a well
by a rope.
The acceleration of gravity is 9.8 m/s
2
.
If the upward acceleration of the bucket is
4.2 m/s
2
, find the force exerted by the rope
on the bucket.

a) First I calculated the force for the rope going upward using the formula f=ma. Since it gave acceleration and mass i multiplied (4.2 m/s^s) and (5 kg) to get a force of 21 upward.

b) To calculate the force downward i used Fg= mg. m= 5 kg and g=9.8. I multiplied the twoand got a Fg of 49.

c) I am stuck on where to go from there. Would I subtract the two to get a net force being my final answer?

1 comment:

Naveen V said...

You came very close. Since the formula is Sum of all forces=ma you would add the downward force of gravity to the force of the rope which would equal the mass of the bucket multiplied by upwards acceleration.

If the force of the rope is Fq then
-Fg+Fq=ma

then all you would have to do is add the downward force of gravity to 21 for your answer.