I did P=Po+rogh but it didn't work, I don't know what I'm doing wrong....and I also don't know what numbers I'm supposed to be plugging in: the oil or the water?
It looks as though you have already figured this one out. You probably used the same equation but realized that there is a ρgh term due to the layer of water and another ρgh term due to the layer of oil. Well done.
The term ρgh is the extra pressure due to a fluid of density ρ and height (thickness) h sitting on top of you. In this problem you have two layers of liquid on top of you so you use two separate terms, one for each layer. For the ρgh term due to the oil you use the density of oil and the thickness of the oil. For the ρgh term due to the water you use the density of water and the thickness of water. Hope that helps. Good luck.
3 comments:
It looks as though you have already figured this one out. You probably used the same equation but realized that there is a ρgh term due to the layer of water and another ρgh term due to the layer of oil.
Well done.
How would you determine the height to use? Would it just be the depth of the liquid it gives you or the distance from the top or bottom?
The term ρgh is the extra pressure due to a fluid of density ρ and height (thickness) h sitting on top of you. In this problem you have two layers of liquid on top of you so you use two separate terms, one for each layer. For the ρgh term due to the oil you use the density of oil and the thickness of the oil. For the ρgh term due to the water you use the density of water and the thickness of water.
Hope that helps. Good luck.
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